Δευτέρα 31 Μαρτίου 2008

7



Mate in 4

GEORGE C. ANYFANTIS

"The Problemist's Supplement" PS 1076 (November 2000)

Solution: 1. Rh3! [2. Rxd3 waiting 2. ... Kc1 3. Se3 [4. Rd1#] 3. ... dxe3 4. Rxc3# 3. ... c2 4. Bd2# 2. Sxd3 waiting 2. ... Kxd1 3. Rh2 waiting 3. ... c2 4. Rd2#] 1. ... d2 2. Rxc3+ 2. ... dxc3 3. Se3+ 3. ... Kc1 4. Sd3# 1. ... Kc1 2. Rxd3 [3. Se3 [4. Rd1#] 3. ... dxe3 4. Rxc3# 3. ... c2 4. Bd2#] 2. ... Kc2 3. Se3+ 3. ... dxe3 4. Rxc3# 3. ... Kc1 4. Rd1#

Σάββατο 29 Μαρτίου 2008

6


Mate in 5
GEORGE C. ANYFANTIS
"The Problemist" C 9615 (January 2001)
Solution: 1. Rc3! [2. Be5+ 2. ... Kf5 3. Rc6 [4. Rf6#] 3. ... e3 4. Rf6+ 4. ... Ke4 5. Bg2#] 1. ... e3 2. Rc6 waiting 2. ... Ke4 3. Be5 waiting 3. ... Kf5 4. Rf6+ 4. ... Ke4 5. Bg2# 2. ... Kf5 3. Rf6+ 3. ... Ke4 4. Bg2+ 4. ... Kd4 5. Rc6# 2. ... Kg3 3. Be5+ 3. ... Kxh3 4. Sxe3 [5. Rh6#] 4. ... Kh4 5. Rh6# 1. ... Kf5 2. Rc6 [3. Rf6#] 2. ... e3 3. Rf6+ 3. ... Ke4 4. Bg2+ 4. ... Kd4 5. Rc6#

5



Mate in 4

GEORGE C. ANYFANTIS

"The Problemist' s Supplement" 1101 (January 2001)

Solution: 1. Qe1! [2. Qxe5#] 1. ... e4 2. Qc3 [3. Qxd4#] 2. ... Sd3 3. Qxd4+ 3. ... Se5 4. Qxe5# 1. ... Rd5 2. Qxf2 [3. Se8, Se4#] 2. ... Rxd6 3. Sxd6 [4. Se8, Se4#] 3. ... e4 4. Qd4# 3. ... Sg3/d2 4. Se8# 1. ... Se4 2. Qxe4 [3. Se8, Qxe5#] 2. ... Rxe4 3. Sxh6 [4. Se8, Sxe4, Sg8#] 3. ... Rd4/f4, Sg3, Sd2 4. Se8, Sg8# 3. ... Re3/e2/e1 4. Se8, Sg8/xg4# 1. ... Sd3 2. Qe4 [3. Se8#] 2. ... Rxd6 3. Sxd6 ad lib 4. Se8# 2. ... Rxe4 3. Sxh6 [4. Se8, Sxe4, Sg8#] 3. ... Rd4/f4, Sc5, Sf2, Sg3, Sd2 4. Se8, Sg8# 3. ... Re3/e2/e1 4. Se8, Sg8/xg4#

Παρασκευή 28 Μαρτίου 2008

4



Mate in 3

GEORGE C. ANYFANTIS

Ths Problemist's Supplement PS 1001 (September 2000)

Solution: 1. Sxd6 ( 2. Sf7#) If 1...Sxd6 2 Rxc5 Sxc5/Kd4 3. Qd5# /Qg1# , If 1...Bxc4 2. Sf7 + Kd4 3. Qg1 , If 1...Bxd6 2. d4 + Sxd4 3. Qd5 #

Τετάρτη 26 Μαρτίου 2008

3



Mate in 4

GEORGE C. ANYFANTIS

"The Problemist" C 9593 (November 2000)

Solution: 1. Qg2 (> Sf2+ , Qg6) 1... Sg4 2. Sf2 + Sxf2 3.Qg6 + Ke3 4. Qd3# , If 1...Sd4+ 2. Rxd4+ Bxd4 3. Qg6+ Sf5 4 Qxf5# , If 1.... Sg3 /Sxg1 2. Sf2+ Ke3 3. Sxd1+ Ke4 4 Qc2# If 1...fxQg2 2. Sf2 + Kf3 3. Rf3#

Tricky sacrificial key problem

Δευτέρα 24 Μαρτίου 2008

2



GEORGE C. ANYFANTIS

"The Problemist" (C 9444) November 1999

Mate in 4

Solution: 1. Re3 ! (2.Se5#) 1.... Rxe3 2. Sxd2+ Rxd2 3. Sb3 + Kd3 4 Sd1 # , 1...Rxa2+ 2.Sa4 + Kd5 3. Sxh2 + Rg2 4. Bxg2 #

Two sacrifices to force distant selfblocks . Two batteries (one masked)

1



GEORGE C. ANYFANTIS

"The Problemist" C 9404 (September 1999)

Mate in 2

Solution : 1. Sf4 (2.Sd3) 1...Kxf4 2. Qh2# , 1...Bxf4 2. Qc5# , 1....gf4 2. Rh5 # , 1...Bf1 2. Qxg5 # , 1...Se1 /Sb4 2. Qe3#

Ένα "Μέρεντιθ" με 6 ματ . Η πρώτη σύνθεση μου, που δημοσιεύθηκε στο γνωστό περιοδικό.